{"id":108657,"date":"2023-11-01T02:48:26","date_gmt":"2023-11-01T02:48:26","guid":{"rendered":"https:\/\/science-hub.click\/%E3%82%B0%E3%83%A9%E3%83%B3%E3%83%89%E3%82%AB%E3%83%8E%E3%83%8B%E3%82%AB%E3%83%AB%E3%82%A2%E3%83%B3%E3%82%B5%E3%83%B3%E3%83%96%E3%83%AB-%E5%AE%9A%E7%BE%A9\/"},"modified":"2023-11-01T02:48:26","modified_gmt":"2023-11-01T02:48:26","slug":"%E3%82%B0%E3%83%A9%E3%83%B3%E3%83%89%E3%82%AB%E3%83%8E%E3%83%8B%E3%82%AB%E3%83%AB%E3%82%A2%E3%83%B3%E3%82%B5%E3%83%B3%E3%83%96%E3%83%AB-%E5%AE%9A%E7%BE%A9","status":"publish","type":"post","link":"https:\/\/science-hub.click\/?p=108657","title":{"rendered":"\u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb – \u5b9a\u7fa9"},"content":{"rendered":"

\u5c0e\u5165<\/h2>

\u7d71\u8a08\u7269\u7406\u5b66\u306b\u304a\u3051\u308b\u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb<\/b>\u306f\u3001\u5404\u30b7\u30b9\u30c6\u30e0\u304c\u5916\u90e8\u306e\u30a8\u30cd\u30eb\u30ae\u30fc\u3068\u7c92\u5b50\u306e\u8caf\u8535\u5eab\u3068\u5e73\u8861\u72b6\u614b\u306b\u3042\u308b\u7d71\u8a08\u7684\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb\u3067\u3059\u3002\u3053\u308c\u306f\u3001\u7cfb\u304c\u30a8\u30cd\u30eb\u30ae\u30fc\u3068\u7c92\u5b50\u3092\u8caf\u7559\u5c64\u3068\u4ea4\u63db\u3067\u304d\u308b\u3053\u3068\u3092\u610f\u5473\u3057\u307e\u3059\u3002\u8a00\u3044\u63db\u3048\u308c\u3070\u3001\u30a8\u30cd\u30eb\u30ae\u30fc\u3068\u7c92\u5b50\u306e\u6570\u306f<\/a><\/span>\u3001\u5168\u4f53\u3068\u3057\u3066\u3042\u308b\u7cfb\u304b\u3089\u5225\u306e\u7cfb\u3078\u3068\u5909\u52d5\u3057\u307e\u3059\u3002<\/p>

\u3053\u306e\u30bb\u30c3\u30c8\u306f<\/a><\/span>\u3001\u7c92\u5b50\u306e\u6570\u3092\u56fa\u5b9a\u3067\u304d\u306a\u3044\u5834\u5408\u3001\u7279\u306b\u30dc\u30fc\u30bd\u30f3\u3068\u30d5\u30a7\u30eb\u30df\u7c92\u5b50\u3067\u69cb\u6210\u3055\u308c\u308b\u7cfb\u306b\u4f7f\u7528\u3055\u308c\u307e\u3059\u3002<\/p>

\n\"\u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb<\/figure>

\u5c0e\u5165<\/h2>

\u3053\u306e\u30bb\u30c3\u30c8\u3067\u306f\u3001\u7cfb\u304c\u540c\u4e00\u306e\u7c92\u5b50\u3067\u69cb\u6210\u3055\u308c\u3066\u3044\u308b\u3068\u8003\u3048\u3001\u7c92\u5b50\u6570\u306e\u5909\u52d5\u3092\u8003\u616e\u3059\u308b\u305f\u3081\u306b\u5316\u5b66\u30dd\u30c6\u30f3\u30b7\u30e3\u30eb\u3092\u5c0e\u5165\u3057\u307e\u3059\u3002\u30a8\u30cd\u30eb\u30ae\u30fc\u3068\u7c92\u5b50\u306e\u4ea4\u63db\u304c\u30ea\u30b6\u30fc\u30d0\u30fc\u306e\u6e29\u5ea6<\/a><\/span>\u3001\u3072\u3044\u3066\u306f\u30b7\u30b9\u30c6\u30e0\u306e\u6e29\u5ea6\u306b\u5f71\u97ff\u3092\u53ca\u307c\u3055\u306a\u3044<\/i>\u3088\u3046\u306b\u3001\u30ea\u30b6\u30fc\u30d0\u30fc\u306f\u30b7\u30b9\u30c6\u30e0\u306e\u524d\u3067\u5927\u304d\u304f\u8003\u616e\u3059\u308b\u5fc5\u8981\u304c\u3042\u308a\u307e\u3059\u3002\u30bf\u30f3\u30af\u306f\u30b5\u30fc\u30e2\u30b9\u30bf\u30c3\u30c8<\/a><\/span>\u306e\u3088\u3046\u306b\u52d5\u4f5c\u3057\u3001\u305d\u306e\u6e29\u5ea6\u3092\u30b7\u30b9\u30c6\u30e0\u306b\u9069\u7528\u3059\u308b\u5fc5\u8981\u304c\u3042\u308a\u307e\u3059\u3002<\/p>

\u30b7\u30b9\u30c6\u30e0\u306e\u30cf\u30df\u30eb\u30c8\u30cb\u30a2\u30f3\u306f\u6b21\u306e\u3088\u3046\u306b\u5b9a\u7fa9\u3055\u308c\u308b\u3068\u8003\u3048\u307e\u3059\u3002 <\/p>

$$ {\\hat H = \\sum_{i=1}^{N} \\hat h(i) } $$<\/div><\/dd><\/dl>

\u307e\u305f\u306f

$$ {\\hat h(i) |i\\rangle = E_i |i\\rangle } $$<\/div>\u306f\u5404\u7c92\u5b50 i \u306e\u30b7\u30e5\u30ec\u30fc\u30c7\u30a3\u30f3\u30ac\u30fc\u65b9\u7a0b\u5f0f\u3067\u3059\u3002<\/p>

\u5404\u9855\u5fae\u93e1\u30bb\u30c3\u30c8\u3054\u3068\u306b

$$ {|n\\rangle } $$<\/div> \u3001\u30a8\u30cd\u30eb\u30ae\u30fc\u3068\u95a2\u9023\u3059\u308b\u7c92\u5b50\u306e\u6570\u304c\u5f97\u3089\u308c\u307e\u3059\u3002 <\/p>
$$ { E \\left(|n\\rangle\\right) = \\sum_i E_i n_i } $$<\/div><\/dd>
$$ { N \\left(|n\\rangle\\right) = \\sum_i n_i } $$<\/div><\/dd><\/dl>

\u8003\u616e\u3055\u308c\u3066\u3044\u308b\u7cfb\u304c\u30dc\u30bd\u30f3\u3067\u69cb\u6210\u3055\u308c\u3066\u3044\u308b\u304b\u30d5\u30a7\u30eb\u30df\u30aa\u30f3\u3067\u69cb\u6210\u3055\u308c\u3066\u3044\u308b\u304b\u306b\u5fdc\u3058\u3066\u3001 ni<\/i>\u306f<\/i><\/sub><\/span>\u6b21\u306e\u6761\u4ef6\u306b\u5f93\u3044\u307e\u3059\u3002 <\/p>

$$ {n_i =\\begin{cases} 0,…,\\infty & \\text{pour les bosons } \\\\ 0,1 & \\text{pour les fermions} \\end{cases}} $$<\/div><\/dd><\/dl>

\u9855\u5fae\u93e1\u3067\u89b3\u5bdf\u3067\u304d\u308b\u3082\u306e<\/h2>

\u30d1\u30fc\u30c6\u30a3\u30b7\u30e7\u30f3\u6a5f\u80fd<\/a><\/span><\/span><\/h3>

\u30d1\u30fc\u30c6\u30a3\u30b7\u30e7\u30f3\u95a2\u6570\u306f\u6b21\u306e\u3088\u3046\u306b\u5b9a\u7fa9\u3055\u308c\u307e\u3059\u3002 <\/p>

$$ { \\Xi = \\sum_{\\{|n_i\\rangle\\} } e^{ -\\beta \\big[ E \\left(|n\\rangle\\right) – \\mu N\\left(|n\\rangle\\right)\\big] } = \\sum_{ \\{ |n_i \\rangle \\} } e^{ -\\beta \\sum_i \\left(E_i – \\mu \\right)n_i }} $$<\/div><\/dd><\/dl>

\u307e\u305f\u306f

$$ {{\\{|n_i\\rangle\\} }} $$<\/div>\u3059\u3079\u3066\u306e\u9855\u5fae\u93e1\u30bb\u30c3\u30c8\u306e\u7d71\u8a08\u30bb\u30c3\u30c8\u3092\u8868\u3057\u307e\u3059
$$ {|n\\rangle } $$<\/div> \u3002<\/p>

\u039e \u306f<\/span>\u6b21\u306e\u3088\u3046\u306b\u66f8\u304f\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002 <\/p>

$$ {\\Xi = \\big( \\sum_{n_1} e^{ -\\beta \\left(E_1 – \\mu \\right)n_1 } \\Big) \\big( \\sum_{n_2} e^{ -\\beta \\left(E_2 – \\mu \\right)n_2 } \\Big)… = \\prod_i \\Xi_i} $$<\/div><\/dd><\/dl>

\u3068

$$ {\\Xi_i = \\big( \\sum_{n_i} e^{ -\\beta \\left(E_i – \\mu \\right)n_i } \\Big)} $$<\/div> \u3001\u5358\u4e00\u30e2\u30fc\u30c9\u306e\u30d1\u30fc\u30c6\u30a3\u30b7\u30e7\u30f3\u95a2\u6570\u3092\u8868\u3057\u307e\u3059\u3002<\/p>
\n\"\u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb<\/figure>

\u5fae\u5c0f\u72b6\u614b\u306e\u78ba\u7387<\/a><\/span><\/span><\/h3>

\u30b7\u30b9\u30c6\u30e0\u304c\u30df\u30af\u30ed\u72b6\u614b i \u306b\u3042\u308b\u78ba\u7387\u306f\u6b21\u306e\u3088\u3046\u306b\u5b9a\u7fa9\u3055\u308c\u307e\u3059\u3002 <\/p>

$$ {p_i = \\frac{e^ { -\\beta \\left(E_i – \\mu \\right)n_i }} {\\Xi}} $$<\/div><\/dd><\/dl>

\u307e\u305f\u306f

$$ { \\sum_{i} p_i \\ = \\ 1} $$<\/div><\/p><\/div>
\n\"\u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb<\/figure>

\u53c2\u8003\u8cc7\u6599<\/h2>
  1. Menge (Mathematik) \u2013 al\u00e9manique<\/a><\/li>
  2. \u1235\u1265\u1235\u1265 \u2013 amharique<\/a><\/li>
  3. \u0645\u062c\u0645\u0648\u0639\u0629 (\u0631\u064a\u0627\u0636\u064a\u0627\u062a) \u2013 arabe<\/a><\/li>
  4. Conxuntu \u2013 asturien<\/a><\/li>
  5. \u00c7oxluqlar \u2013 azerba\u00efdjanais<\/a><\/li>
  6. \u041a\u04af\u043c\u04d9\u043a\u043b\u0435\u043a \u2013 bachkir<\/a><\/li><\/ol><\/div>\n
    \n

    \n \u30b0\u30e9\u30f3\u30c9\u30ab\u30ce\u30cb\u30ab\u30eb\u30a2\u30f3\u30b5\u30f3\u30d6\u30eb – \u5b9a\u7fa9\u30fb\u95a2\u9023\u52d5\u753b\n <\/h2>\n
    \n \n
    \n
    \n